Express the product of \(4 - 3i\) and \(2 + i\) in simplest \(a + bi\) form.

(4-3i)(2+i)=8+4i-6i-3i^2=8-2i+3=11-2i recall that i*i= -1

Answered by daniela88 | 2024-06-10

11-2i ;

Answered by habibsadiq5 | 2024-06-12

The product of the complex numbers 4 − 3 i and 2 + i is 11 − 2 i . This is found by using the distributive property to multiply the two numbers, simplifying the expression, and recalling that i 2 = − 1 . Hence, the final result is in the form a + bi .
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Answered by daniela88 | 2024-09-30