Convert all the mL to L first, .25 L and .84 L (.25) (.5) = (.84) (x) solve... I got .148809524, round to one sig fig (i think) would be .1 M
Answer: a) 0.15 M ;
The molarity of the resulting NaCl solution after dilution is approximately 0.15 M. This was determined using the dilution formula M 1 V 1 = M 2 V 2 . Thus, the correct answer is a) 0.15 M.
;