How many grams of [tex]$CO_2$[/tex] are produced when 80.0 g of [tex]$O_2$[/tex] react with 13.2 g of [tex]$C_3H_8$[/tex] according to the following equation?
[tex]C_3H_8 + 5O_2 \rightarrow 3CO_2 + 4H_2O[/tex]
Answer (2)
For each C3H8, you get 3 C's in CO2, so 13.2 x 3 = 39.6 For each O2, you use 5 to make 3 O2s, so (80/5)3 = 48 39.6+48= 87.6 grams
To determine how many grams of C O 2 are produced from the reaction between 80.0 g of O 2 and 13.2 g of C 3 H 8 , we first identify C 3 H 8 as the limiting reactant. This results in approximately 39.5 g of C O 2 being generated based on the stoichiometry of the reaction.
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