3Cl2 + 2Al ---> 2AlCl3 you're pretty much trying to find the lcm to balance the equation aka you have 2 Cl's on one side and 3 on the other... lcm=6 so put a 3 before Cl2 and a 2 before AlCl3 (since thats one big compound you cant divide it) now since Al has 2 on one side, you need to make sure it has the same amound on the other... so 3, 2 --> 2
Balanced equation looks like this: 3Cl2+2Al=====> 2AlCl3 Its the answer.
The balanced equation for the reaction between chlorine gas and aluminum is 3Cl₂ + 2Al → 2AlCl₃. This ensures that the number of each type of atom is equal on both sides of the equation. Balancing involves finding a common multiple for the number of atoms of reactants and products.
;