How many grams of CO₂ are produced by burning 8.32 g of C₄H₁₀?
Answer (2)
\,\,\, \,\,\, 8.32\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x\\ 2C_4H_1_0+9O_2\to 8CO_2+10H_2O \\ \,\,\, \,\,\,\,\,58\cdot2\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,44\cdot8 \\ \\ \frac{8.32}{58} = \frac{x}{44} \\ \\ x= \dfrac{8.32\cdot44\cdot8}{58\cdot2} =25.2\,\,g
Answer: 25.2 g.
Burning 8.32 g of C₄H₁₀ produces approximately 25.13 g of CO₂. This calculation involves finding the number of moles of butane and using the stoichiometry of the combustion reaction. Ultimately, the conversion leads us to the final mass of carbon dioxide produced during combustion.
;
