The rock in a lead ore deposit contains 84% PbS by mass. How many kilograms of the rock must be processed to obtain 2.3 kg of Pb?

Well take 2.3 kg and divide it by .84 to get 2.738 kg then divide the percent of S in the compounds by adding the atomic masses and dividing the atomic mass of S by the atomic mass of the molecule to get 13.40% S by mass Then you know that Pb is 86.6% by mass so divide 2.738 by .866 to get your answer. Your answer is 3.162 kg of rock is needed

Answered by jonericfogg | 2024-06-10

Answer: 3.162 kg ;

Answered by Edufirst | 2024-06-11

To obtain 2.3 kg of lead from lead ore that is 84% PbS, about 3.162 kg of rock must be processed. This is calculated using the molar masses of Pb and PbS and the mass percent of PbS in the rock. By following the stoichiometric relationships between these substances, we establish the necessary quantities needed for extraction.
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Answered by Edufirst | 2024-10-09