If a radioisotope has a half-life of 10 years, how much of the original material would remain after 40 years?

1/8 would remain... (1/2 is 10 years 1/4 is 20 years 1/8 is 40 years)
Hope this helps! :)

Answered by Bekamop99 | 2024-06-10

Instead of dividing the material by half each time, start by dividing 40 years by the half life of ten. This gives you 4. Subtract 1 So you the answer is 1/2 to the 3rd power

Answered by icedraptor88 | 2024-06-10

After 40 years, 6.25% of the original radioisotope remains due to its half-life of 10 years. Each half-life reduces the remaining amount by half. The calculation shows that after 4 half-lives, the remaining amount is 6.25% of the initial quantity.
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Answered by Anonymous | 2024-12-26