For I- protons = atomic no. = 53 neutrons = atomic mass - atomic number = (127 - 53) = 74
Since it has a negative positive charge, to find the no. of electrons, we need to add 1 to the number of protons, i.e. electrons = (53 + 1) = 54
And, For, Li+
protons = atomic no. = 3 neutrons = atomic mass - atomic number = (7 - 3) = 4
Since it has a positive charge, to find the no. of electrons, we need to subtract 1 form the number of protons, i.e. electrons = (3 - 1) = 2
These are two questions and two answers.
Question 1: protons, electrons, and neutrons in I⁻
Answer: 53 protons, 54 electrons, and a variable number of neutrons. One possibility is 74 neutrons, if it is the most stable isotope, iodine-127. ;
The iodide ion (I - ) has 53 protons, 54 electrons, and 74 neutrons, while the lithium ion (Li + ) has 3 protons, 2 electrons, and 4 neutrons.
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