Yiska has 56 photographs left to scan. If she can scan 6 photographs per minute, in how many minutes will she have fewer than 20 photographs left to scan?

x = minutes
6x = 36 (because she can scan 6 per minute and if she wants 20 left its 56-20)
x = 6 minutes

Answered by ljones1 | 2024-06-10

There are **more **than 6 minutes she has **less than **20 left to scan.
Used the concept of **inequality **that states,
A relation by which we can compare two or more mathematical expressions is called an inequality.
Given that,
Yiska has 56 **photographs **left to scan.
Here, she can scan 6 more photographs per minute.
Let a number of minutes will she have less than 20 left to scan = m
Hence the inequality become for the given condition is,
56 - 6m < 20
Solve for m,
56 < 20 + 6m
56 - 20 < 6m
36 < 6m
6 < m
Therefore, the **solution **for the **number **of minutes is m > 6.
To learn more about **inequality **visit:
https://brainly.com/question/25944814
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Answered by alifaijal77 | 2024-06-18

Yiska needs to scan for more than 6 minutes to have fewer than 20 photographs left. The inequality we set up was 56 − 6 m < 20 , which solved to 6"> m > 6 . Therefore, she has to scan longer than 6 minutes.
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Answered by alifaijal77 | 2025-03-31