1. I drop a penny from the top of the tower at the front of Fort Collins High School and it takes 1.85 seconds to hit the ground.
Calculate the velocity in m/s after 1.10 seconds of freefall.
Calculate the velocity at impact in mi/hr.
Answer (3)
The **velocity at impact in mi/hr is v = 41 mi/hr **if the drop a penny from the top of the **tower **in front of Fort Collins High School , and it takes **1.85 **seconds to hit the ground .
What is the distance?
Distance is a **numerical **representation of the **distance **between two items or locations . Distance refers to a **physical **length or an approximation based on other physics or common usage considerations .
It is given that:
I drop a **penny **from the top of the tower in front of Fort Collins High School and it takes 1.85 seconds to hit the ground .
As we know,
From the **motion **equation:
v= u + at
The acceleration (a) due to **gravity **g = 9.81 m/s²
t = 1.85 seconds
Initial velocity u = 0 m/s
v = 0 + 9.8(1.85)
v = 18.13 m/s
To **convert **miles/hour:
Multiply the speed value by 2.237
v = 40.95 m/s
Or
v = 41 mi/hr
Thus, the **velocity at impact in mi/hr is v = 41 mi/hr **if the drop a penny from the top of the **tower **in front of Fort Collins High School , and it takes **1.85 **seconds to hit the ground .
Learn more about the distance here:
brainly.com/question/26711747
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You have three known variables:
Acceleration - 9.8 m / s 2 Time - 1.85 s Initial Velocity - 0 m / s
For the first part of your question:
[v = u + at
v = (0)+(9.8)(1.1)
v = 10.78 m/s v=11 m/s (2 significant figures)]
For the second part of your question:
[v=u+at
v=(0)+(9.8)(1.85) v=18.13 m/s
]
This still needs to be converted to m/h:
[18.13m/s = 18.13\times 3600 metres/h=65628 metres/hour
65628 metres/hour = 65628\div1600 mi/h = 40.7925 mi/h
= 41 mi/hr (2 significant figures) ]
The velocity of the penny after 1.10 seconds of free fall is approximately 10.79 m/s. At impact, after 1.85 seconds, its velocity is approximately 40.73 mi/hr.
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