4\ or\ 7m < -35\\\\\#1\\5+m > 4\ \ \ \ |subtract\ 5\ from\ both\ sides\\\\m > -1\\\\\#2\\7m < -35\ \ \ \ \ |divide\ both\ sides\ by\ 7\\\\m < -5\\\\Answer:m\in(-\infty;-5)\ \cup\ (-1;\ \infty)"> 5 + m > 4 or 7 m < − 35 #1 5 + m > 4 ∣ s u b t r a c t 5 f ro m b o t h s i d es m > − 1 #2 7 m < − 35 ∣ d i v i d e b o t h s i d es b y 7 m < − 5 A n s w er : m ∈ ( − ∞ ; − 5 ) ∪ ( − 1 ; ∞ )
The inequalities are solved separately: for 5+m>4, subtracting 5 from both sides gives m>-1; for 7m<-35, dividing both sides by 7 gives m<-5. The overall solution to the compound inequality is m>-1 or m<-5.
To solve the inequality 5 + m > 4 or 7m < -35, we can treat each part of the compound inequality separately.
For the first inequality:
5 + m > 4
Subtract 5 from both sides: m > -1
For the second inequality:
7m < -35
Divide both sides by 7: m < -5
So, the solution to the compound inequality is m > -1 or m < -5. This means that the value of m can be any number greater than -1 or less than -5.
To solve the inequalities, we have: 4"> 5 + m > 4 which gives -1"> m > − 1 and 7 m < − 35 which gives m < − 5 . The combined solution is m ∈ ( − ∞ , − 5 ) ∪ ( − 1 , ∞ ) , meaning m can be less than -5 or greater than -1. This indicates two separate ranges of values for m .
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