turn it into exponent form, so Log(1/6)36 ⇒ (1/6)^x=36
6²=36
(1/6)²=(1²/6²)=1/36 so Log(1/6)36=2 :) hope that helped...
log 6 1 ( 36 ) = − 2 ;
The value of lo g 6 1 36 is calculated to be -2. This is derived from the properties of logarithms, using the fact that 36 = 6 2 . Ultimately, we express it as the negative logarithm of base 6 leading to the final answer.
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