What is the slope of a line parallel to the line \(4x - 3y = 16\)?

"Parallel" means the same, which means the slope you find. The formula for slopes is y=mx+b, so we need to put this equation in the right order for that. ('m' is the slope.) Add 4x to each side, and get -3y=16+4x. Rearrange it to get it in the right order (y=mx+b). This is -3y=4x+16. So the number in front of 'x' is 'm', which is the slope. You never actually see 'm', it is represented by a number. So four is the slope.

Answered by bowdenrockz | 2024-06-10

the given eqaution y=mx+b represents a straight line with slope m and the y intercept b.
So now let us see how to graph the equation y=5x+(-6):
Putting x=0, we get y=-6 which implies one coordinate is (0,-6)
Now putting x=1, we get y=-1 which implies the coordinate is (1,-1)
Putting x=2, we get y=4. So the coordinate is (2,4) ;

Answered by raphaelford343 | 2024-06-12

The slope of the line 4 x − 3 y = 16 is found to be 3 4 ​ after rearranging the equation into slope-intercept form. Parallel lines have the same slope, so the slope of any parallel line is also 3 4 ​ .
;

Answered by bowdenrockz | 2024-11-01