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In Mathematics / High School | 2014-11-01

Cory's average score after 8 tests is 91%. If he gets a 78% on his 9th test, what will his new average be?

How do I figure out this problem?

Asked by trevensirboz123

Answer (3)

You should be able to multiply 91 by 8 to get the sum of the first 8 tests, then add the score on the 9th test. Then to get the average of the sum of the 9 tests you need to divide it by 9. ((91*8)+78)/9=89.555555555555.... So, 90%

Answered by 187Blank | 2024-06-10

Cory's new average after a 9th test with a 78% score was approximately 89.56%.
To calculate Cory's new average after taking the 9th test, you would first determine the total score he had after 8 tests and then add the score of the 9th test to find the combined total.
Then, you would divide that sum by the number of tests to find the new average.
Since Cory's average after 8 tests is 91%, his total score for those tests is 8 tests x 91% = 728%.
Add the score of the 9th test: 728% + 78% = 806%.
Divide the combined total by the number of tests: 806% / 9 tests
= 89.56%,
Thus, 89.56 is Cory's new average score.

Answered by AliciaAugello | 2024-06-25

To calculate Cory's new average after 9 tests, first determine the total score for the first 8 tests, which is 728. After adding the 9th test score of 78, the total becomes 806. Dividing this by 9 gives an average of approximately 90%.
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Answered by 187Blank | 2024-10-01