What is the ratio of heterozygous offspring to total offspring in the Punnett square?
Answer (3)
what are the genotypes of the parents? if the parents are homozygous recessive, and homozygous dominant( like TT and tt) it would be: T T t[Tt][Tt] t[Tt][Tt] Which would make heterozygous(Tt) 100%
HOWEVER, if BOTH parents are homozygous dominant, or homozygous recessive(TT, or tt)
like so T T T[TT][TT] T[TT][TT] none would be heterozygous.
if both parents are heterozygous(Tt)(which I'm guessing is the case) T t T[TT][Tt] t [Tt][tt] Than your percentage would be 50% (2:4 ratio)
IF you could specify the genotype, that would be great.
The ratio of heterozygous offspring to total offspring in a Punnett square, for a typical monohybrid cross from heterozygous parents, is usually 1:2, meaning half of the offspring would be heterozygous. ;
The ratio of heterozygous offspring to total offspring is calculated using a Punnett square by counting the genotypes. For two heterozygous parents (Aa x Aa), the ratio is 2 heterozygous out of 4 total, simplifying to 1:2 or 50%. This demonstrates the probability of offspring genotypes based on parental allele combinations.
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