[1], [3] => a = 49,000/2 = 24,500 => b +c = 24,500 => c = 24,500 - b; [2] => 25 24,500 + 20b + 15c = 1,052,000 => 20b + 15c = 1,027,500; 20b + 15 (24,500 - b) = 1,027,500 => 5b = 733,500 => b = 146,700 => c = - 122,200;
To solve simultaneous equations, first express one variable in terms of another, then substitute to find values for both variables. After solution, check by plugging the values back into the original equations. This systematic approach works for various simultaneous equations.
;