{ 5 x + 2 y = 30 5 x + y = 0 ∣ ∗ ( − 2 ) { 5 x + 2 y = 30 − 10 x − 2 y = 0 + − − − − − El imina t i o n m e t h o d 5 x = 30 ∣ d i v i d e b y 5 x = 6 y = − 5 x = − 5 ∗ 6 = − 30 S o l u t i o n : { x = 6 y = − 30
To solve the system of equations, we used the elimination method by manipulating the first equation to eliminate y . After adding the modified equations, we solved for x and then substituted to find y . The final solution is x = − 6 and y = 30 .
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