A golf club with 65 J of kinetic energy strikes a stationary golf ball with a mass of 46 g. The energy transfer is only 20% efficient. Calculate the initial speed of the golf ball.
Answer (3)
kinetic energy of golf club = 65J, kinetic energy supplied to golf ball = 20% of 65 = 0.2 * 65 = 13J, kinetic energy of ball = [mass * Velocity²]/2, mass = 46gm = 0.046Kg, [0.046 * V²]/2 = 13, or 0.046 *V² = 26, V² = 26/0.046 = 565.22, V = 23.77 m/sec = initial velocity of golf ball after hitting.
The **initial velocity **of the ball is v = 23.8 m/s
How to find the initial speed?
We know that kinetic energy is given by:
KE = m*v²/2
Where m is the mass in kg, and we know that the energy transfer is 20% of the intial 65J, then we can write:
0.2*65 = (0.046)*v²/2
Solving this equation for v, the velocity, we get:
v = √[0.2 65 2/0.046]
v = 23.8 m/s
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The initial speed of the golf ball is calculated to be approximately 23.8 m/s after the club transfers 20% of its 65 J of kinetic energy to the ball. The process involves finding the effective energy transfer and using the kinetic energy formula to solve for speed. The mass of the ball is converted from grams to kilograms for accurate calculations.
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