A 2-kg object is thrown vertically upward with an initial kinetic energy of 400 joules. To what height will the object rise?
Answer (3)
initial kinetic energy = 400J, initial kinetic energy = [mass * Velocity²]/2 = [m * V²]/2, [2 * V²]/2 = 400, V² = 400, V = √400 = 20 m/sec, this V is initial velocity of object & it will keep on decreasing due to opposing gravitational force. At one point this will become zero & after that object will start to fall downward. If h is the maximum height it can reach, g is acceleration due to gravity & Vf if final velocity, then we can write, Vf² - V² = -2 g h, ( -ve sign because gravity acts downward) 0 - (20²) = -2 9.81 h, 19.62*h = 400, h = 400/19.62 = 20.38m.
At " 20.38 m " height, the object will be rise. A further explanation is below..
Given:
Initial Kinetic energy ,
400 J
Mass ,
2 kg
As we know the formula,
→ I ni t ia l K . E = 2 ma ss × v e l oc i t y 2
→ 400 = 2 2 × V 2
V 2 = 400
V = 20 m / sec
hence,
→ V f 2 − V 2 = − 2 g h
0 − ( 20 ) 2 = − 2 × 9.81 × h
19.62 × h = 400
h = 19.62 400
= 20.38 m
Thus the above answer is right.
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https://brainly.com/question/3678943
The 2-kg object will rise to a height of approximately 20.38 meters before it starts to descend. This is determined using the conservation of energy, where the initial kinetic energy is converted into gravitational potential energy. The calculations involve basic formulas for kinetic and potential energy.
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