Workers load a 500 kg safe onto an elevator that lifts it 90 m to the twentieth floor of a building. How much work did the elevator do on the safe?

Work is Force X Distance. The force is equal to mass X acceleration (F=MA). In this case the acceleration is gravity, which is 9.81 m/s^2. So you multiply 500 by 9.81 to get 4905 Newtons (N). This is the amount of force required to lift the safe. Multiply this force by the distance, which in this case is 90 meters. This gives you 441450 Newton Meters (N m) of work. 1 N m is equivalent to 1 Joule (J), so the answer can be written as 441450 Joules (J).

Answered by Stude707 | 2024-06-10

The amount of work done on the safe by the elevator is equal to 441,000 Joules or 441 Kilojoules .
Given the following data:

Mass of safe = 500 kg

Displacement = 90 meters


Scientific data:

Acceleration due to gravity = 9.8 m / s 2

To determine the amount of work done on the safe by the elevator :
First of all, we would calculate the magnitude of force that is acting on the safe;
F orce = m g F orce = 500 × 9.8
Force = 4900 Newton
Now, we can determine the amount of work done on the safe :
Mathematically, work done is given by the formula :
W or k d o n e = F orce × d i s pl a ce m e n t W or k d o n e = 4900 × 90
Work done = 441,000 Joules or 441 Kilojoules .
Read more here: https://brainly.com/question/1281428

Answered by Lanuel | 2024-06-15

The work done by the elevator on the safe can be calculated using the formula for work, resulting in 441,000 Joules. This is determined by calculating the weight of the safe and multiplying it by the height it was lifted. The formula used is Work = Force x Displacement, where the force is equal to the weight of the safe.
;

Answered by Lanuel | 2024-12-26