-1.3\\\\p\ \in\ (-1.3;\ 1.3)"> ∣ p ∣ < 1.3 ⇔ p < 1.3 an d p > − 1.3 p ∈ ( − 1.3 ; 1.3 )
[|p|<1.3\ p<1.3\wedge p>-1.3\ p\in(-1.3,1.3)
]
To solve the inequality ∣ p ∣ < 1.3 , we break it down into two inequalities: p < 1.3 and -1.3"> p > − 1.3 . This results in the combined solution − 1.3 < p < 1.3 , or expressed in interval notation as p ∈ ( − 1.3 , 1.3 ) .
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