How do you find the acceleration of a car between two points on a velocity-time graph?

The magnitude of acceleration is
(change in speed) divided by (time for the change) .
Between the two points on the graph ...
-- Find the change in speed. (usually the y-axis) -- Find the change in time. (usually the x-axis)
Divide (change in time) by (change in speed) between the two points. That quotient is the average magnitude of acceleration during that time.
If the graph happens to be a straight line, then the magnitude of acceleration is just the slope of the line.

Answered by AL2006 | 2024-06-10

a = ∆v/∆t Say velocity is on the y-axis and time in on the x-axis. If you take the points (2,1) and (5,8) for example, the difference between the velocity points is 8-1 = 7. This difference is the change in velocity (i.e. ∆v, ∆ means change in) between these two points. The same goes for time: 5-2 = 3. So we've concluded that in this example, ∆v = 7 and ∆t = 3. Now put these into the equation above to find acceleration: 7/3 = 2.333... So the acceleration between these two points on the graph is 2.333...(recurring), or as a fraction, 7/3.

Answered by dannyboy49 | 2024-06-10

To find the acceleration of a car on a velocity-time graph, calculate the change in velocity and the change in time between two points. Then, divide the change in velocity by the change in time to get the average acceleration. This can also be interpreted as the slope of the line connecting those two points on the graph.
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Answered by AL2006 | 2024-12-26