y=3x+40 y=8x+20 when they are the same 3x+40=8x+20 x=4 so at 4 sessions they will be the same but the one that charges 8 per class will become more costly
We are tasked with finding out after how many exercise classes the monthly cost of joining two different gyms will be the same. Let's define two equations to represent the monthly cost (C) for each gym:
Gym A: C = 40 + 3x (where x is the number of exercise classes) Gym B: C = 20 + 8x
To find the point where the cost is the same, we set the two equations equal to each other:
40 + 3x = 20 + 8x
Solving for x, we subtract 3x from both sides:
40 = 20 + 5x
And then subtract 20 from both sides:
20 = 5x
Divide both sides by 5 to find x:
x = 4
So, after 4 exercise classes, the monthly cost will be the same for both gyms. To find the cost:
C = 40 + 3(4) = 40 + 12 = 52
Thus, the cost will be $52 after 4 classes at either gym.
The monthly costs of both gyms become equal after attending 4 exercise classes, with a total cost of $52. This is calculated using cost equations for each gym. By solving the equation where the costs are equal, we find both expenses match at 4 classes and $52.
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