HRS - Ask. Learn. Share Knowledge. Logo

In Mathematics / High School | 2014-11-16

Jill's fish weighs 8 times as much as her parakeet. Together, the pets weigh 63 ounces.

How much does the fish weigh?

Asked by trplet3

Answer (3)

The weight of fish is 56 ounces .
Given,
Fish weight is eight times the weight of parakeet .
So ,
let x =the **weight **of the parakeet.
Then,
**8x **= weight of the fish.
Now ,
**Total **weight of fish and parakeet is 63 ounces .
So,
x+8x=63
9x=63
x = 7
So the **weight **of fish is 8x . Thus
Weight of fish = 8* 7 Weight = 56 ounces
Know more about algebra ,
https://brainly.com/question/16934260
#SPJ6

Answered by rairicha556 | 2024-06-17

let x =the weight of the parakeet. 8x=weight of the fish.
x+8x=63 <-weight of fish and parakeet together equals 63 ounces. SOLVE FOR X. 9x=63. /9 /9 x=7 <-- parakeet weighs 7 ounces. 8x= 8(7). 8x7= 56. the fish weighs 56 ounces.

Answered by ntangerine5 | 2024-06-24

Jill's fish weighs 56 ounces, which is 8 times the weight of her parakeet. The parakeet weighs 7 ounces, and together they weigh 63 ounces. This was calculated using an equation based on the weights of both pets.
;

Answered by rairicha556 | 2024-09-26