Solve the equation:

\[ x^4 + 4x^3 + 7x^2 + 16x + 12 = 0 \]

7xh2+16x=-3-12
7xh2+16x=-15

Answered by Soccergirl101 | 2024-06-10

The equation x 4 + 4 x 3 + 7 x 2 + 16 x + 12 = 0 has the real root x = − 3 and x = − 1 , along with the complex roots x = 2 i and x = − 2 i . By testing possible rational roots and using synthetic division, we successfully factored and solved the polynomial. The final roots include two real and two complex solutions.
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Answered by Anonymous | 2024-12-26