2 in 1. Intermediate Algebra

so the first one is (7x)^(1/2) or square root of 7x minus - 5 square root all squared so
([7x^(1/2)]-[5^(1/2)]) times ([7x^(1/2)]-[5^(1/2)])
or 7x-(35x^(1/2))-5+(35x^(1/2)) or 7x-5
number 2 since 11 is 1/2 of 22 it can be written as
the square root of 3 or 3^(1/2)

Answered by apologiabiology | 2024-06-10

This response breaks down the expressions involving square roots, demonstrating how to expand and simplify them using properties of exponents and binomials. It also touches upon the concept of imaginary numbers when dealing with square roots of negative values. By explaining these principles, the answer provides a comprehensive overview of the topic presented in the question.
;

Answered by apologiabiology | 2024-12-26