The initial population of a town is 127,866, and it grows with a doubling time of 18 years. What will the population be in 23 years?

The difference between 18 and 23 is 5, therefore 18/5= 3.6 From this, after the 18 years, the population will have doubled to 255732. Then to find the increase, you will use 3.6 as percent, and this will be 9206 people added in the population, therefore, making the total population 246938 after 23 years. Hope this helps

Answered by HolmesNWatson | 2024-06-10

To calculate the projected population of a town with an initial population of 127,866 and a doubling time of 18 years after 23 years, we can use the formula for exponential growth. The doubling time formula states:
N = N0 × 2(t/T)
Where:
N is the future population,
N0 is the initial population,
t is the time elapsed,
T is the doubling time.
Using this formula, the calculation is as follows:
N = 127,866 × 2(23/18)
This results in:
N = 127,866 × 21.2778
Approximately N ≈ 127,866 × 2.395 = 306,371
So, after 23 years, the population of the town is expected to be about 306,371 people.

Answered by Qwbox | 2024-06-19

After 23 years, the population of the town will grow to approximately 310,020, starting from an initial population of 127,866 and doubling every 18 years. This involves calculating a complete doubling in 18 years and then using the growth formula to estimate growth over the remaining 5 years. The estimated population reflects the impact of exponential growth over time.
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Answered by HolmesNWatson | 2024-12-26