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In Mathematics / High School | 2014-11-17

pls help....................

Asked by eslaney01

Answer (2)

b 2 + 6 b = 0 b ( b + 6 ) = 0 b = 0 ∨ b = − 6 5 x 2 − 5 x = 0 5 x ( x − 1 ) = 0 x = 0 ∨ x = 1 − 10 x + 35 x = 0 25 x = 0 x = 0 2 x + 15 x = 0 17 x = 0 x = 0 18 x 2 + 6 x = 0 6 x ( 3 x + 1 ) = 0 x = 0 ∨ x = − 3 1 ​ − 32 x 2 − 24 x = 0 − 8 x ( 4 x + 3 ) = 0 x = 0 ∨ x = − 4 3 ​

Answered by konrad509 | 2024-06-10

To solve quadratic equations, techniques such as factoring and the quadratic formula can be used. By factoring, you break down the equation into simpler binomials; alternatively, the quadratic formula handles any quadratic of the form a x 2 + b x + c = 0 . Both methods yield the solutions of the quadratic equation effectively.
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Answered by konrad509 | 2024-12-26