Solve \(|2x + 13| < 15\).

-15\\ 2x<2 \wedge2x>-28\\ x<1 \wedge x>-14\\ x\in(-14,1)"> ∣2 x + 13∣ < 15 2 x + 13 < 15 ∧ 2 x + 13 > − 15 2 x < 2 ∧ 2 x > − 28 x < 1 ∧ x > − 14 x ∈ ( − 14 , 1 )

Answered by konrad509 | 2024-06-10

The solution to the inequality ∣2 x + 13∣ < 15 is − 14 < x < 1 , written in interval notation as ( − 14 , 1 ) . This means that any value of x in that range will satisfy the inequality. We solved the inequality by breaking it down into two separate inequalities based on the definition of absolute value.
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Answered by Anonymous | 2024-12-26