Solve \(|10x + 15| \geq 105\).

∣10 x + 15∣ ≥ 105 5∣2 x + 3∣ ≥ 105 ∣2 x + 3∣ ≥ 21 2 x + 3 ≥ 21 ∨ 2 x + 3 ≤ − 21 2 x ≥ 18 ∨ 2 x ≤ − 24 x ≥ 9 ∨ x ≤ − 12 x ∈ ( − ∞ , − 12 ⟩ ∪ ⟨ 9 , ∞ )

Answered by konrad509 | 2024-06-10

To solve ∣10 x + 15∣ ≥ 105 , we separate it into two cases: 10 x + 15 ≥ 105 leads to x ≥ 9 , and 10 x + 15 ≤ − 105 leads to x ≤ − 12 . Thus, the complete solution is x ≤ − 12 or x ≥ 9 .
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Answered by Anonymous | 2024-12-26