A quadratic equation of the form \(0 = ax^2 + bx + c\) has a discriminant value of \(-16\). How many real number solutions does the equation have?

A quadratic equation with a discriminant value of -16 has no real number solutions. ;

Answered by Qwship | 2024-06-24

The discriminant of a quadratic is given as b 2 − 4 a c , so we know that b 2 − 4 a c = − 16.
When using the quadratic formula to calculate values for x , we have to take the root of the discriminant. There is no real answer to the root of a negative number and so the equation has no real roots.

Answered by superkoopasirf | 2024-07-01

The quadratic equation with a discriminant of − 16 has no real number solutions. This is because a negative discriminant indicates that the roots are complex. Therefore, the equation will have two complex solutions instead of real ones.
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Answered by superkoopasirf | 2024-08-11