{ 2 x + 4 y = 30 ∣ ∗ ( − 3 ) 3 x − 6 y = − 3 ∣ ∗ 2 { − 6 x − 12 y = − 90 6 x − 12 y = − 6 + − − − − e l imina t i o n 0 = − 69 T h ere a re n o so l u t i o n s
We solved the system of equations by first simplifying and aligning the coefficients, then using elimination to find y = 4 and substituting back to find x = 7 . Thus, the solution is x = 7 and y = 4 .
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