The formula for the area of a triangle is [tex]A = \frac{1}{2}bh[/tex], where [tex]b[/tex] is the base of the triangle and [tex]h[/tex] is the height of the triangle.
What is the length of the base if the area is [tex]22 \, \text{cm}^2[/tex] and the height is [tex]8 \, \text{cm}[/tex]?
Answer (3)
The length of the base of the triangle is 5.5 cm, calculated using the formula for area A = 2 1 bh with A = 22 cm² and h = 8 cm.
Given that the area of the triangle is A = 2 1 bh and the height h = 8 cm , and the area A = 22 cm 2 , we can rearrange the formula to solve for the base b:
A = 2 1 bh 22 cm 2 = 2 1 × b × 8 cm 22 cm 2 = 4 b
Now, let's solve for b:
b = 4 22 cm 2 b = 5.5 cm
So, the length of the base of the triangle is 5.5 cm .
The correct question is:
The formula for the area of a triangle is A = 1/2 bh, where b is the base of the triangle and h is the height of the triangle. What is the length of the base if the area is 32 cm^2 and the height is 4cm?
The formula for the area of a triangle is given by the formula:
A = 1/2 * base * height
To find the length of the base of a triangle with an area of 22 cm² and a height of 8 cm, we can rearrange the formula to solve for the base:
base = (2 * area) / height
Plugging in the values, we have: base = (2 * 22 cm²) / 8 cm = 44 / 8 = 5.5 cm.
The length of the base of the triangle is 5.5 cm, calculated using the area formula. Given the area of 22 cm² and the height of 8 cm, the calculations show that b = 8 44 = 5.5 cm .
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