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In Mathematics / High School | 2014-11-17

Point O is the center of the circle in the diagram. What is
m∠BCA?

Asked by ashlybean

Answer (3)

As you know the exterior angle formed by m< BOA is 250 degrees.
The point where C is the point of vertical angles. Vertical angles form a linear pair. Linear pair is Always of 180 degrees so, 250 - 180 = 70 degrees

Answered by aannad1 | 2024-06-10

we know that
The measure of the external angle is the semidifference of the arcs that it covers.
so
m an g l e BC A = 2 1 ​ ∗ ( a rc BO A − a rc B A ) m an g l e BC A = 2 1 ​ ∗ ( 250 − 110 ) m an g l e BC A = 70 d e g rees
therefore
the answer is
The measure of angle BCA is equal to 70 d e g rees

Answered by calculista | 2024-06-24

To find m ∠ BC A , use the formula 2 1 ​ ( a rc BO − a rc B A ) . If, for example, a rc BO = 250° and a rc B A = 110° , then m ∠ BC A = 70° . Substitute the actual arc measures you have into the formula to compute the angle correctly.
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Answered by calculista | 2024-08-16

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