A 4.0-kilogram ball moving at 8.0 m/s to the right collides with a 1.0-kilogram ball at rest. After the collision, the 4.0-kilogram ball moves at 4.8 m/s to the right.
What is the velocity of the 1.0-kilogram ball?
Answer (3)
Its about momentum. Momentum (p)=mass(m)xvelocity(v) So for the first ball P=4x8=32kgm/s For the second the momentum is zero as it is still. So overall momentum its 32kgm/s Momentum has to be conserved After the collision the momentum of the 4kg ball is 4x4.8=19.2kgm/s As momentum is conserved 32-19.2=12.8kgm/s remaining So rearrange for velocity so v=p/m=12.8/1=12.8m/s for the 1kg ball
To calculate the velocity of the ball having less mass after the collision, we use the equation of law of conservation of momentum, which is:
m 1 u 1 + m 2 u 2 = m 1 v 1 + m 2 v 2
where,
m 1 = mass of ball 1 = 4.0 kg
u 1 = Initial velocity of ball 1 = 8.0 m/s
v 1 = Final velocity of ball 1 = 4.8 m/s
m 2 = mass of ball 2 = 1.0 kg
u 2 = Initial velocity of ball 2 = 0 m/s
v 2 = Final velocity of ball 2 = ?
Putting values in above equation, we get:
( 4.0 × 8.0 ) + ( 1.0 × 0 ) = ( 4.0 × 4.8 ) + ( 1.0 × v 2 ) v 2 = 1 32 − 19.2 = 12.8 m / s
Hence, the velocity of ball having less mass is 12.8 m/s
The velocity of the 1.0-kilogram ball after the collision is 12.8 m/s to the right. This is determined using the conservation of momentum principle, which states that the total momentum before the collision equals the total momentum after the collision. By performing the calculation with the given values, we find the result.
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