Input in standard form the equation of the line that passes through \((-2, 4)\) and is parallel to \(x - 2y = 6\).
Answer (2)
x − 2 y = 6 − 2 y = − x + 6 y = 2 1 x − 3 e q u a t i o n o f l in e p a r a ll e l t o \given \one y = a x + b I f l in e i s p a r a ll e l a = 2 1 y = 2 1 x + b S u b s t i t u t in g p o in t ( − 2 , 4 ) 4 = − 2 ∗ 2 1 + b 4 = − 1 + b b = 5 Eq u a t i o n o f l in e y = 2 1 x + 5 St an d a r df or m : − 2 1 x + y = 5
The equation of the line that passes through the point (-2, 4) and is parallel to the line given by x − 2 y = 6 is x − 2 y = − 10 in standard form. First, we determine that the slope of the parallel line is 2 1 and substitute the point to find the y-intercept. Finally, we convert the equation to standard form.
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