f in d 5 2 o f 4 3 5 2 ∗ 4 3 = 20 6 = 10 3 10 3 o f cere a l w ere e a t e n .
the box contains cereal. Only 3/4 of the box has cereal remaining.
From the remaining cereal fraction, 2/5th is consumed.
then the portion of cereal consumed is
5 2 o f 4 3
when the 'of' function is used it means the fractions should be multiplied
then numerators should be multiplied by numerators and denominators by denominators
5 ∗ 4 2 ∗ 3 = 20 6
this can be further simplified by dividing both numerator and denominator by a factor common to both , in this case both 6 and 20 are divisible by 2
20 6 /2 = 10 3
answer is 3/10th of the box is consumed
You eat 10 3 of the entire box of cereal by consuming 5 2 of the remaining 4 3 of the box. To find this, we multiply the fractions together and simplify. The final answer is 10 3 .
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