Find an ordered pair that satisfies the following system of equations:

1. [tex]4c = 3d + 3[/tex]
2. [tex]c = d - 1[/tex]

4 c = 3 d + 3 c = d − 1 s u b s t i t u t e c = d − 1 in t o f i rs t e q 4 ( d − 1 ) = 3 d + 3 4 d − 4 = 3 d + 3 d = 7 c = 7 − 1 = 6

Answered by luana | 2024-06-10

The ordered pair that satisfies both equations is (6, 7).
To find an ordered pair (c, d) that satisfies the equations 4 c = 3 d + 3 and c = d − 1 ,[/tex] we can substitute the expression for c from the second equation into the first equation.
Given [tex] c = d − 1 , we can substitute d − 1 for c in the first equation:
4 ( d − 1 ) = 3 d + 3
Now, let's solve for d:
4 d − 4 = 3 d + 3
Subtract 3d from both sides:
d − 4 = 3
Add 4 to both sides:
d = 7
Now that we have found d=7 we can substitute this value into the second equation to find c:
c = 7 − 1 c = 6

Answered by nehhaaira | 2024-06-25

The ordered pair that satisfies the given system of equations is (6, 7). To find this pair, we substituted the expression for c from the second equation into the first equation and simplified to find the values of c and d. Finally, we confirmed that c = 6 and d = 7 satisfies both equations.
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Answered by nehhaaira | 2025-03-14