Solve the equation [tex]2x^2 - x = 1[/tex].

First move all terms to the same side. 2x^2-x-1=0 Factor this to get (2x+1)(x-1)=0 Separate into 2x+1=0 and x-1=0 Solve these two to get X=-1/2 or x=1 Final answer: X=-1/2 or x=1

Answered by FirstSineOfMadness | 2024-06-10

2 x 2 − x = 1 ∣ s u b t r a c t 1 2 x 2 − x − 1 = 0 u se f a c t or i z a t i o n : w r i t e − x a s x − 2 x 2 x 2 + x − 2 x − 1 = 0 x ( 2 x + 1 ) − 1 ( 2 x − 1 ) = 0 ( x − 1 ) ( 2 x + 1 ) = 0 x = 1 or 2 x = − 1 x = 1 or x = − 2 1 ​

Answered by luana | 2024-06-10

To solve the equation 2 x 2 − x = 1 , we rearrange it to 2 x 2 − x − 1 = 0 and factor it to ( x − 1 ) ( 2 x + 1 ) = 0 . This results in two solutions: x = 1 and x = − 2 1 ​ .
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Answered by luana | 2024-09-05