5 = x 2 + 2 x x 2 + 2 x − 5 = 0 x 2 + 2 x + 1 − 6 = 0 ( x + 1 ) 2 = 6 x + 1 = 6 ∨ x + 1 = − 6 x = − 1 + 6 ∨ x = − 1 − 6
The solutions to the equation 5 = x 2 + 2 x are x = − 1 + 6 and x = − 1 − 6 , both of which are real numbers. There are no imaginary roots since the discriminant is positive. Thus, the equation has two distinct real solutions.
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