Solve the inequality:

[tex] \frac{x+1}{x-8} \leq 0 [/tex]

D : x  = 8 x − 8 x + 1 ​ ≤ 0 ( x + 1 ) ( x − 8 ) ≤ 0 x ∈ ⟨ − 1 , 8 ⟩ x ∈ ⟨ − 1 , 8 ⟩ ∧ x  = 8 x ∈ ⟨ − 1 , 8 ) ​

Answered by konrad509 | 2024-06-10

To solve the inequality x − 8 x + 1 ​ ≤ 0 , determine the critical points by setting the numerator and denominator to zero. The solution includes values from − 1 to just below 8 , so x ∈ [ − 1 , 8 ) .
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Answered by Anonymous | 2025-06-13