In 25 years, how much movement will result from a fault that slowly slips 1.5 centimeters per year?

1.5 centimeters x 25= 37.5

Answered by Allisa | 2024-06-10

Over 25 years, a fault that slips 1.5 centimeters per year will exhibit a total movement of 37.5 centimeters.

To determine how much movement a fault that slips 1.5 centimeters per year will experience over 25 years, we simply perform a multiplication of the yearly slip rate by the number of years. The calculation is as follows:
Identify the annual slip rate of the fault: 1.5 centimeters per year.
Multiply the annual slip rate by the time period: 25 years.
Calculate the total movement: 1.5 cm/year times 25 years = 37.5 centimeters.
Therefore, in 25 years, the fault will have moved a total of 37.5 centimeters.

Answered by ShrutiSharma11 | 2024-06-24

In 25 years, a fault that slips 1.5 centimeters annually will move a total of 37.5 centimeters. This is calculated by multiplying the annual slip rate by the number of years. Therefore, the movement is 1.5 cm/year times 25 years, which equals 37.5 cm.
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Answered by ShrutiSharma11 | 2024-12-26