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In Mathematics / High School | 2014-11-19

em I right on #9 & 10 algebra 2

Asked by bella122

Answer (2)

#9 is correct. #10 is actually choice 2. This is because the difference of logs with the same base (log(x)-log(y)) is equal to the log of the two numbers divided by each other, so log(x)-log(y) would equal log(x/y). In your case, log(15)-log(10) => log(15/10) => log(3/2), final answer.

Answered by FirstSineOfMadness | 2024-06-10

For #9, the correctness can't be confirmed without seeing the specific problem. For #10, the answer is lo g ( 3/2 ) using logarithmic properties. Ensure the application of the rules is correct for both questions.
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Answered by FirstSineOfMadness | 2024-12-26

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