Use the substitution method to solve the system of equations:

1. [tex]x = 4[/tex]
2. [tex]2x - 3y = -19[/tex]

\left\{\begin{array}{ccc}x=4\\2x-3y=-19\end{array}\right\\\left\{\begin{array}{ccc}x=4\\2\cdot4-3y=-19\end{array}\right\\\left\{\begin{array}{ccc}x=4\\8-3y=-19\end{array}\right\\\left\{\begin{array}{ccc}x=4\\-3y=-19-8\end{array}\right\\\left\{\begin{array}{ccc}x=4\\-3y=-27&/:(-3)\end{array}\right\\\left\{\begin{array}{ccc}x=4\\y=9\end{array}\right

Answered by Anonymous | 2024-06-10

2(4)-3y=-19 8-3y=-19 -3y=-27 y=9

Answered by HannahN | 2024-06-10

By substituting x = 4 into the second equation 2 x − 3 y = − 19 , we found y = 9 . Thus, the solution to the system of equations is x = 4 and y = 9 . Verifying these values in the original equations confirms their correctness.
;

Answered by Anonymous | 2024-12-20