**3. Factor.**
\[ 9x^2 + 15x \]
A. \( x(3x + 5) \)
B. \( 3x(3x + 5) \)
C. \( 9x(x + 5) \)
D. \( 3x^2(3x + 5) \)
**4. Factor.**
\[ 20mn − 30m \]
A. \( 2m − 3 \)
B. \( 10m(2n − 3) \)
C. \( 10mn(2m + 3n) \)
D. \( 10n(2m − 3) \)
**5. Factor.**
\[ 8x^2y^2 − 4x^2y − 12xy \]
A. \( 4(2xy − 4x^2y − 12xy) \)
B. \( 4(8x^2y^2 − x − 12xy) \)
C. \( 4x^2y^2(2xy − xy − 3) \)
D. \( 4xy(2xy − x − 3) \)
Answer (2)
It seems that some the work is already here, but I'd be glad to!! So for #3 which is 9x^2+15x, we can factor out both a 3 and an x (3x) so we know that 3x * 3x =9x^2 and 3x * 5 = 15x so once we take the 3x out of the equation, we are left with 3x(3x+5) and that's as far as you can factor. For #4, we see that the common factor is 10m because 10m * 2n = 20mn and 10m * 3 = 30m so once we take 10m out of the original, it becomes 10m(2n-3) For #5, this one the common factor is 4xy because 4xy * 2xy=8x^2y^2 and 4xy x= 4x^2y and 4xy 3=12xy so once we take the 4xy out of the equation, it becomes 4xy(2xy-x-3) Hope this helps!
The factors for each expression are: 3) B. 3 x ( 3 x + 5 ) , 4) B. 10 m ( 2 n − 3 ) , and for 5) the factors are ideally 4 x y ( 2 x y − x − 3 ) . However, option correctness may vary for question 5 but remains factorizable as explained from the logic provided.
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