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In Mathematics / High School | 2014-03-16

Arnold had $1.70 in dimes and quarters. He had 3 more dimes than quarters. How many of each coin did he have?

Asked by odamm

Answer (3)

four quarters and seven dimes
Each quarter is 25 cents so, $0.25 * 4 = $1.00 Each dime is 10 cents so, $0.10 * 7 = $0.70
So, $1.00 + $0.70 = $1.70

Answered by Paigee | 2024-06-10

Answer: 4 quarters 7 dimes
Step-by-step explanation: 4 quarters is $1, 4 + 3 is 7, each dime is worth 10 cents, so 70 cents. $1 + .70 = $1.70

Answered by dwayneterrell | 2024-06-12

Arnold has 4 quarters and 7 dimes. The total value of the coins is $1.70, with the dimes being 3 more than the number of quarters. This was derived by setting up equations based on the coin values and their quantities.
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Answered by Paigee | 2025-03-06