The perimeter of a regular nonagon is 18 inches. Is that enough information to find the area? If so, find the area and explain your steps. If not, explain why not.
Answer (2)
The information is **enough **to find the area. Then the area of the **regular nonagon **will be 24.73 square inches.
Given that:
Perimeter, P = 18 inches
The **side length **of the regular nonagon is calculated as,
9x = 18 inches
x = 2 inches
The regular nonagon is divided into 9 **isosceles **triangles. Then the **height **of the isosceles triangle is calculated as,
sin (180° - 360°/9)/2 = h/(2/2)
tan 70° = h / 1
h = 7.7474 inches
The **area **of the regular nonagon will be calculated as,
A = 9 x (1/2 x 2.7474 x 2)
A = 9 x 2.7474
A = 24.73 square inches
The information is **enough **to find the area. Then the area of the **regular nonagon **will be 24.73 square inches.
More about the **perimeter **of the regular **polygon **link is given below.
https://brainly.com/question/10885363
#SPJ1
The perimeter of the regular nonagon is sufficient to calculate the area, which is approximately 3.27 square inches. To find this, I first calculated the length of each side and then applied the area formula for a regular nonagon. The height of the triangles formed by the nonagon's sides was also needed for the area calculation.
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