What strategy would you use to solve these multiplication problems involving 3 and 7?
1. \(8 \times 3\)
2. \(7 \times 4\)
Answer (2)
8 ⋅ 3 = 7 ⋅ 3 + 3 7 ⋅ 4 = 7 ⋅ 3 + 7
To solve 8 × 3 , we can express 8 as 7 + 1 , resulting in 24 . For 7 × 4 , rewriting 4 as 3 + 1 gives us 28 . Both strategies use the distributive property for easier calculations.
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