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In Mathematics / High School | 2014-03-18

A forest inhabited only by borogoves and mome raths contains 82 creatures. Borogoves are two-legged animals, while mome raths have four legs. If the forest contains a total of 234 legs, how many borogoves and how many mome raths live in the forest?

Asked by Stefon627

Answer (2)

To find the number of borogoves and mome raths, set up a system of equations using the total number of creatures and the total number of legs. Solve the system to find that there are 47 borogoves and 35 mome raths in the forest.
The question involves solving a system of linear equations to determine the number of two types of animals, borogoves and mome raths, in a forest based on the total number of creatures and the total number of legs.

Let x be the number of borogoves and y be the number of mome raths in the forest.
Since we know there are a total of 82 creatures, we can write the first equation as x + y = 82.
We also know that borogoves have 2 legs and mome raths have 4 legs, and there are a total of 234 legs in the forest. This gives us the second equation 2x + 4y = 234.
Simplify the second equation to x + 2y = 117 by dividing every term by 2.
Subtract the first equation from the simplified second equation: (x + 2y) - (x + y) = 117 - 82, which simplifies to y = 35.
Substitute the value of y into the first equation: x + 35 = 82, which simplifies to x = 47.

Therefore, the forest contains 47 borogoves and 35 mome raths.

Answered by Yakavi | 2024-06-24

There are 47 borogoves and 35 mome raths in the forest, based on the total number of creatures and legs. This was determined using a system of equations. The equations were solved step-by-step to find the values for each type of creature.
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Answered by Yakavi | 2024-10-10