Solve by Substitution:

\[ y = -\frac{3}{2}x - 4 \]

\[ y = -\frac{1}{2}x + 1 \]

\left\{\begin{array}{ccc}y=-\frac{3}{2}x-4\\\\y=-\frac{1}{2}x+1\end{array}\right\\\\-\frac{3}{2}x-4=-\frac{1}{2}x+1\ /\cdot2\\\\-3x-8=-x+2\\\\-3x+x=2+8\\\\-2x=10\ /:(-2)\\\\x=-5\\\\y=-\frac{1}{2}\cdot(-5)+1=2,5+1=3,5\\\\ \left\{\begin{array}{ccc}x=-5\\y=3,5\end{array}\right

Answered by Anonymous | 2024-06-10

{ y = − 2 3 ​ x − 4 y = − 2 1 ​ x + 1 ​ { y = − 2 3 ​ x − 4 − 2 3 ​ x − 4 = − 2 1 ​ x + 1 ​ { y = − 2 3 ​ x − 4 − 2 3 ​ x + 2 1 ​ x = 1 + 4 ​ { y = − 2 3 ​ x − 4 − 2 2 ​ x = 5 ​
{ y = − 2 3 ​ x − 4 − x = 5/ ∗ ( − 1 ) ​ { y = − 2 3 ​ ∗ ( − 5 ) − 4 x = − 5 ​ { y = 2 15 ​ − 4 x = − 5 ​ { y = 7 2 1 ​ − 4 x = − 5 ​ { y = 3 2 1 ​ x = − 5 ​

Answered by Anonymous | 2024-06-10

To solve the equations y = − 2 3 ​ x − 4 and y = − 2 1 ​ x + 1 by substitution, we set them equal to each other and found that x = − 5 . Substituting this back into either original equation gives y = 2 7 ​ , leading to the solution ( x , y ) = ( − 5 , 2 7 ​ ) .
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Answered by Anonymous | 2024-12-20